[F:1][C:2]1[CH:3]=[CH:4][C:5]([CH3:10])=[C:6]([CH:9]=1)[CH:7]=O.[C:11]([O:21][CH2:22][CH3:23])(=[O:20])[CH:12]=CC1C=CC=CC=1>>[F:1][C:2]1[CH:3]=[CH:4][C:5]([CH3:10])=[C:6](/[CH:7]=[CH:12]/[C:11]([O:21][CH2:22][CH3:23])=[O:20])[CH:9]=15-Fluoro-2-methylbenzaldehyde (40.58 g; 294 mmol) was converted to the ethyl cinnamate according to step 1 of example 1 to yield 40.81 g. of the title compound.
Wird geladen…