Hydrogen iodide → 2-hexylthio-7-iodo-5H-1,3,4-thiadiazolo[3,2-a]pyrimidin-5-one
Reaktionsgleichung
Cl[C:2]1[N:3]=[C:4]2[S:11][C:10]([S:12][CH2:13][CH2:14][CH2:15][CH2:16][CH2:17][CH3:18])=[N:9][N:5]2[C:6](=[O:8])[CH:7]=1.[IH:19]>>[I:19][C:2]1[N:3]=[C:4]2[S:11][C:10]([S:12][CH2:13][CH2:14][CH2:15][CH2:16][CH2:17][CH3:18])=[N:9][N:5]2[C:6](=[O:8])[CH:7]=1Komponenten
3
Versuchsvorschrift
A solution of 8.4 g of the thus obtained 7-chloro-2-hexylthio-5H-1,3,4-thiadiazolo[3,2-a]-pyrimidin-5-one and 88.2 g of a 57% hydroiodic acid aqueous solution was heated to 95°~110° C. and stirred for 2 hours. After cooling, the solution was filtered. The residue was washed with water and dissolved in toluene. The toluene solution was washed with a sodium hydrogen carbonate aqueous solution, a sodium thiosulfate aqueous solution and water respectively and dried over anhydrous sodium sulfate. The solvent was distilled off and thus 9.8 g of 80% pure 7-iodo-2-hexylthio-5H-1,3,4-thiadiazolo[3,2-a]pyrimidin-5-one was obtained. Yield 72%.