[Cl:1][CH:2]1[CH:12]=[CH:11][CH:5]2[C:6]([O:8][C:9](=[O:10])[CH:4]2[CH2:3]1)=[O:7].BrBr>>[Cl:1][C:2]1[CH:3]=[C:4]2[C:9](=[O:10])[O:8][C:6](=[O:7])[C:5]2=[CH:11][CH:12]=1A co-pending application, Ser. No. 07/405,606, discloses that 4-chlorotetrahydrophthalic anhydride reacts with elemental bromine to form 4-chlorophthalic anhydride. 4-Bromophthalic anhydride is sometimes found as a side product in low percentage, but is not economically recoverable.
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