[CH3:1][C:2]1[C:6]([C:7]([OH:9])=O)=[CH:5][NH:4][N:3]=1.[CH:10]1([NH2:13])[CH2:12][CH2:11]1>>[CH:10]1([NH:13][C:7]([C:6]2[C:2]([CH3:1])=[N:3][NH:4][CH:5]=2)=[O:9])[CH2:12][CH2:11]1Following the same procedure in Example 29 (Step B and C in Method B), using 3-methyl-1H-pyrazole-4-carboxylic acid (252 mg, 2.0 mmol) and cyclopropylamine (285 mg, 5.0 mmol), provided the desired crude compound (310 mg, 94%), which was used in Step A directly.
Wird geladen…