F[C:2]1[CH:9]=[C:8]([O:10][CH3:11])[CH:7]=[CH:6][C:3]=1[CH:4]=O.[H-].[Na+].[SH:14][CH2:15][C:16]([O:18][CH3:19])=[O:17]>>[CH3:19][O:18][C:16]([C:15]1[S:14][C:2]2[CH:9]=[C:8]([O:10][CH3:11])[CH:7]=[CH:6][C:3]=2[CH:4]=1)=[O:17]Using 2.5 g (16.2 mmol) of 2-fluoro-4-methoxybenzaldehyde, 0.97 g (24.3 mmol) of sodium hydride (60% pure) and 1.89 g (17.8 mmol) of methyl mercaptoacetate, 3.05 g (84.7% of theory) of the title compound are obtained.
Wird geladen…