Ethanethiol → HCID 10366287, Verbindung
Reaktionsgleichung
[F:1][C:2]1[CH:22]=[C:21]([F:23])[CH:20]=[CH:19][C:3]=1[O:4][C:5]1[CH:6]=[C:7]([CH:11]=[CH:12][C:13]=1[NH:14][S:15]([CH3:18])(=[O:17])=[O:16])[C:8](Cl)=[O:9].[S-:24][C:25]#[N:26].[K+].[CH2:28]([SH:30])[CH3:29]>C1(C)C=CC=CC=1>[F:1][C:2]1[CH:22]=[C:21]([F:23])[CH:20]=[CH:19][C:3]=1[O:4][C:5]1[CH:6]=[C:7]([CH:11]=[CH:12][C:13]=1[NH:14][S:15]([CH3:18])(=[O:17])=[O:16])[C:8]([NH:26][C:25](=[S:24])[S:30][CH2:28][CH3:29])=[O:9]Komponenten
5
