[F:1][C:2]1[CH:7]=[CH:6][N:5]=[C:4]([N+:8]([O-])=O)[C:3]=1[OH:11]>C(O)C.[Pd]>[NH2:8][C:4]1[C:3]([OH:11])=[C:2]([F:1])[CH:7]=[CH:6][N:5]=1Under argon, 90 mg (0.57 mmol) of 4-fluoro-2-nitropyridin-3-ol Example 108A were dissolved in 30 ml of ethanol, and a spatula tip of palladium on activated carbon (10%) was added. The mixture was hydrogenated at RT under reduced pressure for 1.5 h. The reaction mixture was filtered off through silica gel and the filter cake was washed with plenty of ethanol. The solution was concentrated and dried. This gave 56 mg (77% of theory) of the title compound.
Wird geladen…