[F:1][C:2]1[CH:3]=[C:4]([NH:8][CH2:9][C:10](O)=[O:11])[CH:5]=[CH:6][CH:7]=1.[BH4-].[Na+].II>>[F:1][C:2]1[CH:3]=[C:4]([NH:8][CH2:9][CH2:10][OH:11])[CH:5]=[CH:6][CH:7]=1Similar procedure as described in example 31a) was used, starting from 3-fluorophenylglycine, sodium borohydride and iodine to give 3-fluoro-Phenylglycinol. LC-MS m/e 156 (MH+).
Wird geladen…