BrBr.[Br:3][C:4]1[C:9]([F:10])=[C:8]([F:11])[C:7]([F:12])=[C:6]([F:13])[C:5]=1Br>>[Br:3][C:4]1[C:9]([F:10])=[C:8]([F:11])[C:7]([F:12])=[C:6]([F:13])[CH:5]=1A residue of 3.9 g consisting of bromine and dibromotetrafluorobenzene remains in the boiler in a ratio of about 1:1. The calculated yield to bromotetrafluorobenzene with respect to the distillate is 33.4%.
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