Br[C:2]1[C:3]([Cl:9])=[C:4](Cl)[CH:5]=[CH:6][CH:7]=1.[Cl:10]C1C(Cl)=C(Cl)C=CC=1.[C:19]([OH:23])(=[O:22])[CH2:20][SH:21].[OH-].[K+]>>[Cl:9][C:3]1[CH:4]=[CH:5][C:6]([Cl:10])=[CH:7][C:2]=1[CH:20]([SH:21])[C:19]([OH:23])=[O:22]Using the combinations of monobromodichlorobenzene or trichlorobenzene, thioglycolic acid, potassium hydroxide and solvent listed in Table 2, the reaction was carried out in the same manner as in Example 8 or 9 to yield 2,5-dichlorophenylthioglycolic acid. The results are given in Table 2.
Wird geladen…