[OH:1][C:2]1[CH:7]=[CH:6][C:5]([CH3:8])=[CH:4][CH:3]=1.Br[CH2:10][C:11]([C:13]1[CH:18]=[CH:17][CH:16]=[CH:15][CH:14]=1)=[O:12]>>[CH3:8][C:5]1[CH:6]=[CH:7][C:2]([O:1][CH2:10][C:11]([C:13]2[CH:18]=[CH:17][CH:16]=[CH:15][CH:14]=2)=[O:12])=[CH:3][CH:4]=1Using the method of Example 17 and starting with 4-hydroxytoluene and α-bromoacetophenone one obtains α-(4-methylphenoxy)-acetophenone.
Wird geladen…