Pentafluoronitrobenzene → 1,2,4,5-Tetrafluoro-3-methoxy-6-nitrobenzene
Reaktionsgleichung
[F:1][C:2]1[C:7]([N+:8]([O-:10])=[O:9])=[C:6]([F:11])[C:5]([F:12])=[C:4](F)[C:3]=1[F:14].[CH3:15][O-:16].[Na+]>CO>[F:1][C:2]1[C:3]([F:14])=[C:4]([O:16][CH3:15])[C:5]([F:12])=[C:6]([F:11])[C:7]=1[N+:8]([O-:10])=[O:9]Komponenten
4
Edukt 2
Produkt 1
Reagenzien, Katalysatoren, Lösungsmittel 1
Versuchsvorschrift
50 g of pentafluoronitrobenzene was dissolved in 400 ml of dry methanol. Thereto was dropwise added, with ice-cooling, a solution of 13.95 g of sodium methoxide dissolved in 50 ml of dry methanol. A reaction was allowed to take place at room temperature for 2 hours. The reaction mixture was concentrated to a volume of about ⅓ under vacuum. The residue was poured into 500 ml of water. The organic layer was extracted with 300 ml of ether. The ether layer was washed with an aqueous sodium chloride solution and dried over MgSO4. The resulting solution was subjected to vacuum distillation to remove the solvent. The residue was subjected to vacuum distillation (96 to 97° C./0.35 mmHg (47 Pa)) to obtain 38 g of 2,3,5,6-tetrafluoro-4-methoxynitrobenzene (yield: 72%).