Formaldehyde → 2-Hydroxy-5-tert-butylbenzyl alcohol
Reaktionsgleichung
[C:1]([C:5]1[CH:10]=[CH:9][C:8]([OH:11])=[CH:7][CH:6]=1)([CH3:4])([CH3:3])[CH3:2].[OH-:12].[Na+].[CH2:14]=O>>[OH:12][CH2:14][C:9]1[CH:10]=[C:5]([C:1]([CH3:4])([CH3:2])[CH3:3])[CH:6]=[CH:7][C:8]=1[OH:11]Komponenten
4
Versuchsvorschrift
The general procedure of Example 35 was repeated except that 50 grams (0.333 mole) of p-tert-butyl phenol was used, along with 14 grams (0.35 mole) of 98% sodium hydroxide and 33.73 grams (0.416 mole) of the formaldehyde solution to obtain the intermediate 2-hydroxymethyl-4-tert-butyl phenol. The desired product, 2-(2-hydroxyethyl)thiomethyl-4-tert-butyl phenol, was obtained from 17.2 grams (0.095 mole) of the intermediate and 7.4 grams of the 2-mercaptoethanol (0.095 mole) in 50 ml of toluene, along with 0.10 gram of the catalyst. Structural formula 26 for the product was confirmed by 1H and 13C NMR.