[CH3:1][C:2]1[CH:7]=[CH:6][C:5]([S:8][C:9]2[CH:14]=[CH:13][C:12]([OH:15])=[CH:11][CH:10]=2)=[C:4]([N+:16]([O-])=O)[CH:3]=1.Cl[Sn]Cl>>[NH2:16][C:4]1[CH:3]=[C:2]([CH3:1])[CH:7]=[CH:6][C:5]=1[S:8][C:9]1[CH:14]=[CH:13][C:12]([OH:15])=[CH:11][CH:10]=1The product from Example 6b (8.65 g, 31.3 mmol) was reduced with SnCl2 following the procedure from Example 5I giving the title compound as a white solid (8.51 g, 100%).
Wird geladen…