Ethyl chloroacetate → HCID 70530867, compound

Reaction equation

[CH3:1][C:2]1[CH:15]=[CH:14][C:5]([S:6][C:7]2[CH:12]=[CH:11][C:10]([OH:13])=[CH:9][CH:8]=2)=[CH:4][CH:3]=1.C(=O)([O-])[O-].[K+].[K+].[CH2:22]([O:24][C:25](=[O:28])[CH2:26]Cl)[CH3:23]>CC(CC)=O>[CH2:22]([O:24][C:25](=[O:28])[CH2:26][O:13][C:10]1[CH:11]=[CH:12][C:7]([S:6][C:5]2[CH:14]=[CH:15][C:2]([CH3:1])=[CH:3][CH:4]=2)=[CH:8][CH:9]=1)[CH3:23]

Participants

Procedure

While stirring, 30 g of 4(4-methylthio-phenoxy)-phenol were dissolved in 350 ml of methylethyl-ketone. After addition of 18 g of potassium carbonate and 16 g of chloroacetic acid ethyl ester, the mixture was heated at the boil for 8 hours. Inorganic components were then separated by suction-filtration. After vaporization of the organic solvent, the residue was dissolved in 300 ml of methylene chloride and the solution was shaken several times with water. The organic phase was vaporized and the residue was distilled in vacuo. 25 g of 4(4-methylthio-phenoxy)-phenoxy-acetic acid ethyl ester were obtained, boiling point: 215°-230°/3-4 mm mercury.