Phosphorus oxide (P4O10) → 1-Cyclohexyl-5-chloro-3,4-dihydroisoquinoline

Reaction equation

[CH:1]1([C:7]([NH:9][CH2:10][CH2:11][C:12]2[CH:17]=[CH:16][CH:15]=[CH:14][C:13]=2[Cl:18])=O)[CH2:6][CH2:5][CH2:4][CH2:3][CH2:2]1.P(Cl)(Cl)(Cl)=O.O=P12OP3(OP(OP(O3)(O1)=O)(=O)O2)=O>>[CH:1]1([C:7]2[C:17]3[C:12](=[C:13]([Cl:18])[CH:14]=[CH:15][CH:16]=3)[CH2:11][CH2:10][N:9]=2)[CH2:6][CH2:5][CH2:4][CH2:3][CH2:2]1

Participants

Reactant 3

HCID 14812Phosphorus oxide (P4O10)

HCID 24813Phosphorus oxychloride

HCID 128518191-Cyclohexylcarbonylamino-2-(2-chlorophenyl)ethane

Product 1

HCID 205338811-Cyclohexyl-5-chloro-3,4-dihydroisoquinoline

Procedure

1-Cyclohexylcarbonylamino-2-(2-chlorophenyl)-ethane, phosphorus oxychloride and phosphorus pentoxide were reacted in the same was as in step (b) of Example 13 to afford 1-cyclohexyl-5-chloro-3,4-dihydroisoquinoline as an oil.

Sources & evidence

ORD record: ord-f6f36ae2e2e44af59a73630a27a5a07d
Source dataset: uspto-grants-1982_06
DOI: 10.6084/m9.figshare.5104873.v1
Patent number: US04337256

Reaction notes

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