Hydrochloric Acid → 6-(9-oxoacridin-10(9H)-yl)hexanoic acid
Reaction equation
[O:1]=[C:2]1[C:15]2[CH:14]=[CH:13][CH:12]=[CH:11][C:10]=2[N:9]([CH2:16][CH2:17][CH2:18][CH2:19][CH2:20][C:21]([O:23]CC)=[O:22])[C:8]2[C:3]1=[CH:4][CH:5]=[CH:6][CH:7]=2.Cl>C(O)(=O)C>[O:1]=[C:2]1[C:15]2[CH:14]=[CH:13][CH:12]=[CH:11][C:10]=2[N:9]([CH2:16][CH2:17][CH2:18][CH2:19][CH2:20][C:21]([OH:23])=[O:22])[C:8]2[C:3]1=[CH:4][CH:5]=[CH:6][CH:7]=2Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 100 °C
Procedure
To ethyl 6-(9-oxoacridin-10(9H)-yl)hexanoate (0.80 g) was added acetic acid (9 ml) and 2M hydrochloric acid (2.5 ml). The mixture was heated to 100° C. for 18 hours after which time the volatile components were removed on a rotary evaporator. Diethyl ether was added (25 ml) and the mixture stirred for 15 minutes. The resulting material was filtered off and air dried to give 0.36 g final product (Formula XVII). Mass spectrum: 310 (M+H).