Sodium Iodide → 3-Methyl-6-(3,4-methylenedioxyphenyl)-3-hexenyl iodide
Reaction equation
[CH3:1][C:2](=[CH:6][CH2:7][CH2:8][C:9]1[CH:14]=[CH:13][C:12]2[O:15][CH2:16][O:17][C:11]=2[CH:10]=1)[CH2:3][CH2:4]Br.[I-:18].[Na+]>CC(C)=O>[CH3:1][C:2](=[CH:6][CH2:7][CH2:8][C:9]1[CH:14]=[CH:13][C:12]2[O:15][CH2:16][O:17][C:11]=2[CH:10]=1)[CH2:3][CH2:4][I:18]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
3-Methyl-6-(3,4-methylenedioxyphenyl)-3-hexenyl iodide [VI; Ar is 3,4-methylenedioxyphenyl, R is CH3 ] was prepared from 19.0 g. of 3-methyl-6-(3,4-methylenedioxyphenyl)-3-hexenyl bromide (Preparation C3) and 10.5 g. of sodium iodide in 125 ml. of acetone, to give 21 g. of product as a yellow oil.
Sources & evidence
- ORD record
- ord-cb0cce58c82045af890f9fd386e66bc1
- Source dataset
- uspto-grants-1980_02
- Patent number
- US04189500
Reaction notes
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