Bromine → 2-Bromo-4-fluoro-5-methoxybenzaldehyde
Reaction equation
[F:1][C:2]1[CH:9]=[CH:8][C:5]([CH:6]=[O:7])=[CH:4][C:3]=1[O:10][CH3:11].[Br-:12].[K+].BrBr>O>[Br:12][C:8]1[CH:9]=[C:2]([F:1])[C:3]([O:10][CH3:11])=[CH:4][C:5]=1[CH:6]=[O:7]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
A solution of 4-fluoro-3-methoxybenzaldehyde (4.3 g, 27.9 mmol), potassium bromide (16.6 g, 139.5 mmol), bromine (3.6 mL, 69.8 mmol), and water (45 mL) were stirred at room temperature for 24 hours. More bromine (1.43 mL, 27.9 mmol) was added and the reaction was stirred at room temperature overnight. The product precipitated out of solution and was collected via filtration and dried under reduced pressure to give 2-bromo-4-fluoro-5-methoxybenzaldehyde (6.01 g, 92% yield).
Workup
- customThe product precipitated out of solution
- filtrationwas collected via filtration
- customdried under reduced pressure
Sources & evidence
- ORD record
- ord-8b8869fc1cd0440990fdc2b74201a5e5
- Source dataset
- uspto-grants-2015_04
- Patent number
- US09012431B2
Reaction notes
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