Reaction equation
C[O:2][CH:3](OC)[C:4]1[CH:5]=[C:6]([C:10]2[CH:15]=[CH:14][N:13]=[C:12]([NH:16][CH2:17][CH2:18][C:19]3[CH:24]=[CH:23][C:22]([OH:25])=[CH:21][CH:20]=3)[N:11]=2)[CH:7]=[CH:8][CH:9]=1.Cl>CC#N>[OH:25][C:22]1[CH:21]=[CH:20][C:19]([CH2:18][CH2:17][NH:16][C:12]2[N:11]=[C:10]([C:6]3[CH:5]=[C:4]([CH:9]=[CH:8][CH:7]=3)[CH:3]=[O:2])[CH:15]=[CH:14][N:13]=2)=[CH:24][CH:23]=1Participants
4
Procedure
Intermediate 27 (2.2 g) was treated with 30 mL of 3N HCl in 60 mL of CH3CN at room temperature overnight. The solvent was removed by rotary evaporation and the residue partitioned between ethyl acetate/sat. NaHCO3. Yield: 1.9 g, 99%. LC-MS showed the product had the expected M+H+ of 320.
Workup
- customThe solvent was removed by rotary evaporation
- customthe residue partitioned between ethyl acetate/
Sources & evidence
- ORD record
- ord-35af2987e5d84ed19c3e51c6c0d54461
- Source dataset
- uspto-grants-2010_06
- Patent number
- US07732444B2
Linked notes
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