Sodium Hydroxide → 3-(Quinolin-8-yl)benzoic acid
Reaction equation
[N:1]1[C:10]2[C:5](=[CH:6][CH:7]=[CH:8][C:9]=2[C:11]2[CH:12]=[C:13]([CH:18]=[CH:19][CH:20]=2)[C:14]([O:16]C)=[O:15])[CH:4]=[CH:3][CH:2]=1.[OH-].[Na+]>C1COCC1>[N:1]1[C:10]2[C:5](=[CH:6][CH:7]=[CH:8][C:9]=2[C:11]2[CH:12]=[C:13]([CH:18]=[CH:19][CH:20]=2)[C:14]([OH:16])=[O:15])[CH:4]=[CH:3][CH:2]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 60 °C
Procedure
820 mg (3.11 mmol) of methyl 3-(quinolin-8-yl)benzoate was dissolved in 8.2 mL of THF, and a 1N aqueous sodium hydroxide solution (4.7 mL) was added thereto at room temperature. The mixture was stirred at 60° C. for 1.5 hours. Thereafter, the organic solvent was distilled off under reduced pressure, H2O was added to the resulting residue, and then dissolution was conducted. Thereafter, 1N hydrochloric acid was added to the resultant at 0° C., and the pH was adjusted to 4. The precipitated solids were collected by filtration and dried, thereby giving 711 mg of 3-(quinolin-8-yl)benzoic acid (yield: 92%).