Potassium Phosphate, Tribasic → 4-[3-(2-triphen ylenyl)phenyl]-Dibenzothiophene

Reaction equation

FC(F)(F)S(O[C:7]1[CH:12]=[CH:11][CH:10]=[C:9]([C:13]2[CH:30]=[CH:29][C:28]3[C:27]4[C:22](=[CH:23][CH:24]=[CH:25][CH:26]=4)[C:21]4[C:16](=[CH:17][CH:18]=[CH:19][CH:20]=4)[C:15]=3[CH:14]=2)[CH:8]=1)(=O)=O.[CH:33]1[C:41]2[C:40]3[CH:42]=[CH:43][CH:44]=[CH:45][C:39]=3[S:38][C:37]=2[C:36](B(O)O)=[CH:35][CH:34]=1.C1(P(C2CCCCC2)C2C=CC=CC=2C2C(OC)=CC=CC=2OC)CCCCC1.[O-]P([O-])([O-])=O.[K+].[K+].[K+]>C1C=CC(/C=C/C(/C=C/C2C=CC=CC=2)=O)=CC=1.C1C=CC(/C=C/C(/C=C/C2C=CC=CC=2)=O)=CC=1.C1C=CC(/C=C/C(/C=C/C2C=CC=CC=2)=O)=CC=1.[Pd].[Pd].O.C1(C)C=CC=CC=1>[CH:14]1[C:15]2[C:16]3[C:21](=[CH:20][CH:19]=[CH:18][CH:17]=3)[C:22]3[C:27](=[CH:26][CH:25]=[CH:24][CH:23]=3)[C:28]=2[CH:29]=[CH:30][C:13]=1[C:9]1[CH:8]=[C:7]([C:36]2[C:37]3[S:38][C:39]4[CH:45]=[CH:44][CH:43]=[CH:42][C:40]=4[C:41]=3[CH:33]=[CH:34][CH:35]=2)[CH:12]=[CH:11][CH:10]=1