Thiophenol → Benzene, 1,4-bis(phenylthio)-
Reaction equation
[OH-].[K+].[C:3]1([SH:9])[CH:8]=[CH:7][CH:6]=[CH:5][CH:4]=1>CC(N(C)C)=O>[S:9]([C:6]1[CH:7]=[CH:8][C:3]([S:9][C:3]2[CH:8]=[CH:7][CH:6]=[CH:5][CH:4]=2)=[CH:4][CH:5]=1)[C:3]1[CH:8]=[CH:7][CH:6]=[CH:5][CH:4]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 120 °C
Procedure
A mixture of 19.6 parts of 86% potassium hydroxide, 33 parts of thiophenol and about 120 parts of dimethylacetamide was heated at a temperature of 120° C. with stirring to effect the removal of water. After about 6.5 parts of water was collected, there was added to the resulting mixture 26.3 parts of para-dibromobenzene and the mixture was heated to reflux. After 6 hours at reflux the reaction mixture was allowed to cool and 300 parts of water was added. There was obtained a tan colored solid which was filtered and washed with water several times. The product was then dried. There was obtained 34.7 parts of 1,4-dithiophenoxybenzene based on method of preparation.