Benzyl Bromide → N,N-bis-(2-hydroxyethyl)-2-fluoro-4-benzyloxyaniline
Reaction equation
[OH:1][CH2:2][CH2:3][N:4]([CH2:13][CH2:14][OH:15])[C:5]1[CH:10]=[CH:9][C:8]([OH:11])=[CH:7][C:6]=1[F:12].[OH-].[K+].[CH:18]1[CH:23]=[CH:22][C:21]([CH2:24]Br)=[CH:20][CH:19]=1>CCO>[OH:1][CH2:2][CH2:3][N:4]([CH2:13][CH2:14][OH:15])[C:5]1[CH:10]=[CH:9][C:8]([O:11][CH2:24][C:21]2[CH:22]=[CH:23][CH:18]=[CH:19][CH:20]=2)=[CH:7][C:6]=1[F:12]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
To a solution of N,N-bis-(2-hydroxyethyl)-2-fluoro-4-hydroxyaniline (2 g) and KOH (0.64 g, 10.0 mmole) in EtOH (13 mL) was added BnBr (1.1 mL, 9.1 mmole) and the reaction mixture stirred at reflux for 3 h. The reaction mixture was cooled, evaporated to in dryness and purified by silica gel chromatography (0-7% MeOH/DCM) to provide N,N-bis-(2-hydroxyethyl)-2-fluoro-4-benzyloxyaniline (2.26 g) as a yellow syrup.