Hydrogen Bromide → Carvedilol HBr
Reaction equation
[CH3:1][O:2][C:3]1[CH:4]=[CH:5][CH:6]=[CH:7][C:8]=1[O:9][CH2:10][CH2:11][NH:12][CH2:13][CH:14]([OH:30])[CH2:15][O:16][C:17]1[CH:18]=[CH:19][CH:20]=[C:21]2[NH:29][C:28]3[CH:27]=[CH:26][CH:25]=[CH:24][C:23]=3[C:22]=12.[BrH:31]>C(O)C.C(O)(=O)C>[CH3:1][O:2][C:3]1[CH:4]=[CH:5][CH:6]=[CH:7][C:8]=1[O:9][CH2:10][CH2:11][NH:12][CH2:13][CH:14]([OH:30])[CH2:15][O:16][C:17]1[CH:18]=[CH:19][CH:20]=[C:21]2[NH:29][C:28]3[CH:27]=[CH:26][CH:25]=[CH:24][C:23]=3[C:22]=12.[BrH:31]Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
Carvedilol free base is dissolved in ethanol, and anhydrous HBr is added (HBr in acetic acid). The solution is cooled, and crystallization ensues. The product is filtered, washed with process solvent, and dried.