Reaction equation
[Mo:1]=[O:2].O.O.O.O.O.[N+]([O-])([O-])=[O:9].[Bi+3:12].[N+]([O-])([O-])=[O:14].[N+]([O-])([O-])=[O:18]>O.[OH-].[NH4+].[N+]([O-])(O)=O>[O-2:9].[O-2:14].[O-2:18].[O-2:2].[O-2:9].[O-2:9].[O-2:9].[O-2:9].[O-2:9].[Mo:1].[Mo:1].[Bi+3:12].[Bi+3:12]Participants
6
Reactant 2
Product 1
Reagents, catalysts & solvents 3
Procedure
28.78 grams of molybdenum oxide (MoO3) were dissolved in a mixture of 72 ml of water and 36 ml of concentrated ammonium hydroxide, added to a solution of 97 grams of bismuth nitrate pentahydrate in ~184 ml of water and 30 ml of concentrated nitric acid with stirring, and the pH of the resulting mixture was adjusted to between 3 and 6.5 using ammonium hydroxide whereafter it was boiled for approximately 3 hours. The precipitate was filtered and washed with approximately 1000 ml of water.
Workup
- filtrationThe precipitate was filtered
- washwashed with approximately 1000 ml of water
Sources & evidence
- ORD record
- ord-87b6e9fd9fff4391a70d71541f468122
- Source dataset
- uspto-grants-1983_09
- Patent number
- US04405498
Linked notes
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