Lithium Hydroxide → 2-Indancarboxylic Acid

HRID 22510

Reaction equation

HRID 22510 reaction equation
[C:1]([C:6]1(C(OCC)=O)[CH2:14][C:13]2[C:8](=[CH:9][CH:10]=[CH:11][CH:12]=2)[CH2:7]1)([O:3]CC)=[O:2].[OH-].[Li+]>C(O)C>[C:1]([CH:6]1[CH2:14][C:13]2[C:8](=[CH:9][CH:10]=[CH:11][CH:12]=2)[CH2:7]1)([OH:3])=[O:2]

Participants

4

Procedure

Dissolve 2,2-dicarboethoxy-indan (5.67 g, 21.7 mmol) in ethanol (150 mL). Add 1N lithium hydroxide (50 mL) and stir overnight at room temperature. Reflux for 1 hour and concentrate the solution in vacuo. Partition between ethyl acetate and 6N hydrochloric acid. Separate the organic phase and wash with brine. Dry (MgSO4) and evaporate the solvent in vacuo to give an off-white solid. Distill (120°-160° C. @0.2-0.5 mmHg) to give 2-carboxy-indan (2.5 g, 71%).

Workup

  1. temperatureReflux for 1 hour
  2. concentrationconcentrate the solution in vacuo
  3. customPartition between ethyl acetate and 6N hydrochloric acid
  4. customSeparate the organic phase
  5. washwash with brine
  6. dry with materialDry (MgSO4)
  7. customevaporate the solvent in vacuo
  8. customto give an off-white solid
  9. distillationDistill (120°-160° C. @0.2-0.5 mmHg)

Sources & evidence

ORD record
ord-288d66e56e5748a3accfe02165bd1989
Source dataset
uspto-grants-1995_06
Patent number
US05428158

Linked notes

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