Hydrogen Bromide → Carvedilol HBr
Reaction equation
[CH3:1][O:2][C:3]1[CH:4]=[CH:5][CH:6]=[CH:7][C:8]=1[O:9][CH2:10][CH2:11][NH:12][CH2:13][CH:14]([OH:30])[CH2:15][O:16][C:17]1[CH:18]=[CH:19][CH:20]=[C:21]2[NH:29][C:28]3[CH:27]=[CH:26][CH:25]=[CH:24][C:23]=3[C:22]=12.[BrH:31]>C(O)CC.O>[CH3:1][O:2][C:3]1[CH:4]=[CH:5][CH:6]=[CH:7][C:8]=1[O:9][CH2:10][CH2:11][NH:12][CH2:13][CH:14]([OH:30])[CH2:15][O:16][C:17]1[CH:18]=[CH:19][CH:20]=[C:21]2[NH:29][C:28]3[CH:27]=[CH:26][CH:25]=[CH:24][C:23]=3[C:22]=12.[BrH:31]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
Carvedilol free base is dissolved in n-propanol/water (95:5), and stoichiometric hydrobromic acid is added. The solution is cooled, and crystallization ensues. The product is filtered, washed with process solvent, and dried.
Workup
- temperatureThe solution is cooled
- customcrystallization ensues