Perchloric Acid → 4-(4'-Fluoro-4-biphenylyl)-butyric acid
Reaction equation
[F:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[CH:13]=[CH:12][C:11]([C:14](=O)[CH2:15][CH2:16][C:17]([OH:19])=[O:18])=[CH:10][CH:9]=2)=[CH:4][CH:3]=1.Cl(O)(=O)(=O)=O>C(O)(=O)C.[Pd]>[F:1][C:2]1[CH:3]=[CH:4][C:5]([C:8]2[CH:13]=[CH:12][C:11]([CH2:14][CH2:15][CH2:16][C:17]([OH:19])=[O:18])=[CH:10][CH:9]=2)=[CH:6][CH:7]=1Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
5.0 gm (0.018 mol) of 4-(4'-fluoro-4-biphenylyl)-4-oxo-butyric acid were hydrogenated in 50 ml of acetic acid under addition of 1.5 ml of perchloric acid in the presence of 1.5 gm of palladium/barium sulfate (5%) as catalyst at room temperature and at a pressure of 5 atmospheres in a Parr-autoclave.