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Hydrochloric Acid → HCID 22640915, compound

HRID 2415309
Notes
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Reaction equation

HRID 2415309 reaction equation
[ClH:1].[OH:2][CH:3]([CH2:17][O:18][C:19]1[C:28]2[C:23](=[CH:24][CH:25]=[CH:26][CH:27]=2)[CH:22]=[CH:21][CH:20]=1)[CH2:4][NH:5][C:6]([CH3:16])([CH3:15])[CH2:7][C:8]1[CH:13]=[CH:12][C:11](F)=[CH:10][CH:9]=1.Cl.[OH:30][CH:31](COC1C=CC=CC=1)CNC(C)(C)CC1C=CC(OC)=CC=1.Cl>C(OCC)C>[ClH:1].[OH:2][CH:3]([CH2:17][O:18][C:19]1[CH:28]=[CH:27][C:26]2[C:21](=[CH:22][CH:23]=[CH:24][CH:25]=2)[CH:20]=1)[CH2:4][NH:5][C:6]([CH3:15])([CH3:16])[CH2:7][C:8]1[CH:9]=[CH:10][C:11]([O:30][CH3:31])=[CH:12][CH:13]=1
ParticipantsProcedureWorkupSources & evidenceReaction notes

Participants

5

Reactant 3

HCID 313Hydrochloric AcidHCID 18459602N-[2-Hydroxy-3-(1-naphthoxy)propyl]-1,1-dimethyl-2-(4-fluorophenyl)ethylamine HydrochlorideHCID 22640854n-(2-Hydroxy-3-phenoxypropyl)-1,1-dimethyl-2-(4-methoxyphenyl)ethylamine hydrochloride

Product 1

HCID 22640915HCID 22640915, compound

Reagents, catalysts & solvents 1

HCID 3283
Diethyl Ether
Solvent

Procedure

Using the method of Example 4, supra, 2-naphthyl glycidyl ether (400 mg, 2 mmol) and 1,1-dimethyl-2-(4-methoxyphenyl)ethylamine (358 mg, 2 mmol) were used to prepare the free base of the title compound: GC/EI-MS, m/z (rel. int.) 364 (M−15, 1), 253 (100), 183 (2), 163 (3), 144 (4), 127 (10), 121 (22), 115 (20), 71 (11). The free base in diethyl ether was treated with excess 1M HCl (diethyl ether). The resulting solid was recrystallized from hot acetonitrile to afford 496 mg of the hydrochloride product as a white solid.

Workup

  1. customThe resulting solid was recrystallized from hot acetonitrile

Sources & evidence

ORD record
ord-e4ac2236f1a94c329f9d4c6f7f4a0208
Source dataset
uspto-grants-2004_11
DOI
10.6084/m9.figshare.5104873.v1
Patent number
US06818660B2

Reaction notes

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On this pageParticipantsProcedureWorkupSources & evidenceReaction notes