Lithium borohydride → (3-Benzyloxy-4-iodophenyl)methanol
Reaction equation
[BH4-].[Li+].[CH2:3]([O:10][C:11]1[CH:12]=[C:13]([CH:18]=[CH:19][C:20]=1[I:21])[C:14](OC)=[O:15])[C:4]1[CH:9]=[CH:8][CH:7]=[CH:6][CH:5]=1>O1CCCC1>[CH2:3]([O:10][C:11]1[CH:12]=[C:13]([CH2:14][OH:15])[CH:18]=[CH:19][C:20]=1[I:21])[C:4]1[CH:5]=[CH:6][CH:7]=[CH:8][CH:9]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 60 °C
Procedure
1.18 g (54 mmol, 3 eq) of lithium borohydride are added to a solution of 6.9 g of methyl 3-benzyloxy-4-iodobenzoate in 30 ml of tetrahydrofuran. The reaction medium is heated at 60° C. for 12 hours and then hydrolyzed with ammonium chloride solution and extracted with ethyl acetate. The organic phases are combined and the solvents are evaporated off. 6.5 g of (3-benzyloxy-4-iodophenyl)methanol in oil form are used in the following reaction without further purification.