Reaction equation
[CH3:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]([O:10]C)=[O:9])=[CH:4][C:3]=1[C:12]([O:14]C)=[O:13].O[Li].O>C1COCC1.CO.O>[CH3:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]([OH:10])=[O:9])=[CH:4][C:3]=1[C:12]([OH:14])=[O:13]Participants
4
Procedure
A solution of 2-20 (1.5 g, 7.2 mmoles) in THF/MeOH/H2O (1:1:1) (36 ml) at room temperature was treated with LiOH.H2O (1.5 g, 36 mmoles). After stirring for 3 hours, the solvent was removed and the residue acidified with 1N HCl. This was extracted with EtOAc, and the extract was dried (MgSO4) and concentrated to give 2-21.
Workup
- customthe solvent was removed
- extractionThis was extracted with EtOAc
- dry with materialthe extract was dried (MgSO4)
- concentrationconcentrated
- customto give 2-21
Sources & evidence
- ORD record
- ord-a4daebdea2f44a1488ff83b844dfc640
- Source dataset
- uspto-grants-1997_07
- Patent number
- US05648368
Linked notes
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