Hydrochloric Acid → Propranolol Hydrochloride

HRID 328887

Reaction equation

HRID 328887 reaction equation
[C:1]1([O:11][CH2:12][CH:13]([OH:19])[CH2:14][NH:15][CH:16]([CH3:18])[CH3:17])[C:10]2[C:5](=[CH:6][CH:7]=[CH:8][CH:9]=2)[CH:4]=[CH:3][CH:2]=1.[ClH:20]>CCOCC>[ClH:20].[C:1]1([O:11][CH2:12][CH:13]([OH:19])[CH2:14][NH:15][CH:16]([CH3:17])[CH3:18])[C:10]2[C:5](=[CH:6][CH:7]=[CH:8][CH:9]=2)[CH:4]=[CH:3][CH:2]=1

Participants

4

Reactant 2

HCID 313Hydrochloric Acid2×HCID 4946Propranolol

Product 1

HCID 62882Propranolol Hydrochloride

Reagents, catalysts & solvents 1

HCID 3283Diethyl EtherSolvent

Procedure

1-(isopropyl)-3-azetidinol and α-naphthol were reacted in the same manner as in Example 6 to form 1-(α-naphthoxy)-3-(iso-propylamino)-2-propanol. Then the propanol was dissolved in anhydrous ether and was converted to a hydrochloride by blowing a hydrochloric acid gas into the resulting solution. As a result 1-(α-naphthoxy)-3-(isopropylamino)-2-propanol hydrochloride melting at 162°-164° C was obtained.

Sources & evidence

ORD record
ord-77ed6ab9cd424e5b846c165a7ead2e71
Source dataset
uspto-grants-1977_04
Patent number
US04018824

Linked notes

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