Chloride → Lidocaine

HRID 342317

Reaction equation

HRID 342317 reaction equation
[CH3:1][CH2:2][N:3]([CH2:6][C:7]([NH:9][C:10]1[C:11]([CH3:17])=[CH:12][CH:13]=[CH:14][C:15]=1[CH3:16])=[O:8])[CH2:4][CH3:5].[ClH:18].[Cl-]>O>[CH3:5][CH2:4][N:3]([CH2:6][C:7]([NH:9][C:10]1[C:15]([CH3:16])=[CH:14][CH:13]=[CH:12][C:11]=1[CH3:17])=[O:8])[CH2:2][CH3:1].[CH3:5][CH2:4][N:3]([CH2:6][C:7]([NH:9][C:10]1[C:15]([CH3:16])=[CH:14][CH:13]=[CH:12][C:11]=1[CH3:17])=[O:8])[CH2:2][CH3:1].[ClH:18]

Participants

5

Reactant 2

HCID 312ChlorideHCID 6314Lidocaine Hydrochloride2×

Product 2

HCID 3676LidocaineHCID 6314Lidocaine Hydrochloride

Reagents, catalysts & solvents 1

HCID 962WaterSolvent

Procedure

In this Example and Comparative Example, a solution with a pH of from about 4.0 to 5.5 of 4.0 weight % lidocaine hydrochloride in deionized water was prepared. The lidocaine hydrochloride solution contained a mixture of chloride ions and protonated lidocaine ions that were formed by dissociation of lidocaine hydrochloride in the solution. The lidocaine hydrochloride solution was injected into the component 12 in Example 4 and into the component 14 in Comparative Example 5. It is believed that the lidocaine hydrochloride solution was absorbed substantially uniformly into both the component 12 and the component 14 in Example 4. The amount of the lidocaine hydrochloride solution that was injected into the electrode of Example 4 was 4 cc, and the amount of the lidocaine hydrochloride solution that was injected into the electrode of Comparative Example 5 was 3 cc, as seen in Table 5 below.

Sources & evidence

ORD record
ord-fdb616c817c8464fb7d56ca8650a865c
Source dataset
uspto-grants-1999_01
Patent number
US05857993

Linked notes

Loading…