Iodoethane → 3-Chloro-4-ethoxybenzaldehyde

Reaction equation

[Cl:1][C:2]1[CH:3]=[C:4]([CH:7]=[CH:8][C:9]=1[OH:10])[CH:5]=[O:6].[CH2:11](I)[CH3:12]>>[Cl:1][C:2]1[CH:3]=[C:4]([CH:7]=[CH:8][C:9]=1[O:10][CH2:11][CH3:12])[CH:5]=[O:6]

Participants

Reactant 2

HCID 6340Iodoethane

HCID 170223-Chloro-4-hydroxybenzaldehyde

Product 1

HCID 47700353-Chloro-4-ethoxybenzaldehyde

Procedure

Following a similar procedure to that described in reference example 3, but starting from 3-chloro-4-hydroxybenzaldehyde instead of 4-hydroxybenzaldehyde and using ethyl iodide instead of 2-iodopropane, the title compound of the example was obtained as an oil (98% yield).

Sources & evidence

ORD record: ord-8ca606ee22674638b03ccc9e17baf9a7
Source dataset: uspto-grants-2004_06
DOI: 10.6084/m9.figshare.5104873.v1
Patent number: US06743816B2

Reaction notes

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