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Thionyl Chloride → (1-Chloroethyl)-2,4-hexadienoate

HRID 35275
Notes
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Reaction equation

HRID 35275 reaction equation
[C:1]([OH:8])(=[O:7])/[CH:2]=[CH:3]/[CH:4]=[CH:5]/[CH3:6].S(Cl)([Cl:11])=O.CC1OC(C)O[CH:16]([CH3:21])O1>[Cl-].[Zn+2].[Cl-]>[Cl:11][CH:16]([O:7][C:1](=[O:8])[CH:2]=[CH:3][CH:4]=[CH:5][CH3:6])[CH3:21]
ParticipantsProcedureWorkupSources & evidenceReaction notes

Participants

5

Reactant 3

HCID 24386Thionyl ChlorideHCID 31264ParaldehydeHCID 643460Sorbic Acid2×

Product 1

HCID 53809045(1-Chloroethyl)-2,4-hexadienoateYield 64.2%

Reagents, catalysts & solvents 1

HCID 3007855ZincchlorideCatalyst

Procedure

A mixture of 5.6 g. (50 mmoles) of sorbic acid and 7.8 g. (65 mmoles) of thionyl chloride was stirred at a room temperature for one hour, and then reacted at 50° C. for 30 minutes with stirring to complete the reaction. The end point of the reaction was judged by cessation of SO2 gas production and disappearance (dissolution) of sorbic acid. The resulting reaction mixture was cooled with ice, and then 0.27 g. (2 mmoles) of 96% zinc chloride was added thereto. After adding dropwise 2.2 g. of paraldehyde at 0° C., the reaction was carried out at a room temperature for one hour. The resulting reaction mixture was treated and purified in the same manner as in Reference Example 1 to give 5.43 g. (yield: 64.2%) of the desired compound being a clear solution.

Workup

  1. additionA mixture of 5.6 g
  2. customreacted at 50° C. for 30 minutes
  3. customthe reaction
  4. customThe resulting reaction mixture
  5. temperaturewas cooled with ice
  6. additionAfter adding dropwise 2.2 g
  7. customThe resulting reaction mixture
  8. additionwas treated
  9. custompurified in the same manner as in Reference Example 1
  10. customto give 5.43 g

Sources & evidence

ORD record
ord-8d3fb801a85840e4b1294e2a03ba2f4c
Source dataset
uspto-grants-1988_08
DOI
10.6084/m9.figshare.5104873.v1
Patent number
US04766148

Reaction notes

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On this pageParticipantsProcedureWorkupSources & evidenceReaction notes