Benzyl Bromide → HCID 23287578, compound
Reaction equation
[NH:1]([C:8]1[S:9][C:10]2[N:18]=[CH:17][CH:16]=[CH:15][C:11]=2[C:12](=[O:14])[N:13]=1)[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1.[H-].[Li+].[CH2:21](Br)[C:22]1[CH:27]=[CH:26][CH:25]=[CH:24][CH:23]=1>>[CH2:21]([N:13]1[C:12](=[O:14])[C:11]2[CH:15]=[CH:16][CH:17]=[N:18][C:10]=2[S:9][C:8]1=[N:1][C:2]1[CH:3]=[CH:4][CH:5]=[CH:6][CH:7]=1)[C:22]1[CH:27]=[CH:26][CH:25]=[CH:24][CH:23]=1Participants
4
Procedure
The reaction procedure of Example 11 was followed except that 150 mg of 2-anilino-4H-pyrido[3,2-e]-1,3-thiazin-4-one, 6 mg of lithium hydride and 0.070 ml of benzyl bromide were used. As a result, 130 mg of 3-benzyl-2-phenylimino-2,3-dihydro-4H-pyrido[3,2-e]-1,3-thiazin-4-one was obtained.
Workup
- customThe reaction procedure of Example 11