Lithium hydroxide, monohydrate → 5-(2,2,2-Trifluoroethoxy)pyridine-2-carboxylic acid
Reaction equation
C[O:2][C:3]([C:5]1[CH:10]=[CH:9][C:8]([O:11][CH2:12][C:13]([F:16])([F:15])[F:14])=[CH:7][N:6]=1)=[O:4].O.[OH-].[Li+]>CO>[F:16][C:13]([F:14])([F:15])[CH2:12][O:11][C:8]1[CH:9]=[CH:10][C:5]([C:3]([OH:4])=[O:2])=[N:6][CH:7]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
Under an atmosphere of nitrogen a solution of 5-(2,2,2-trifluoro-ethoxy)-pyridine-2-carboxylic acid methyl ester (216 mg, 0.92 mmol) in methanol (1 ml) was treated with a solution of lithium hydroxide monohydrate (78 mg, 1.84 mmol) in methanol (0.1 ml). After stirring for 2 hours the reaction mixture was evaporated at reduced pressure. The residue was treated with hydrochloric acid (1N), the solid material was filtered then washed with water, finally dried at high vacuum. The 5-(2,2,2-trifluoro-ethoxy)-pyridine-2-carboxylic acid was obtained as a white solid (125 mg, 61% of theory).