Br[C:2]1[C:7]([NH:8][C:9]2[CH:21]=[CH:20][C:19]([CH3:22])=[CH:18][C:10]=2[C:11]([O:13][C:14]([CH3:17])([CH3:16])[CH3:15])=[O:12])=[CH:6][C:5]([Cl:23])=[CH:4][N:3]=1.[C:24]1(B(O)O)[CH:29]=[CH:28][CH:27]=[CH:26][CH:25]=1>>[Cl:23][C:5]1[CH:6]=[C:7]([NH:8][C:9]2[CH:21]=[CH:20][C:19]([CH3:22])=[CH:18][C:10]=2[C:11]([O:13][C:14]([CH3:17])([CH3:16])[CH3:15])=[O:12])[CH:2]=[N:3][C:4]=1[C:24]1[CH:29]=[CH:28][CH:27]=[CH:26][CH:25]=1Obtained (0.005 g, 3% of yield) following the procedure described in Example 8 (step A) starting with 0.230 g (0.58 mmol) of Intermediate 20A and 0.106 g (0.87 mmol) of phenylboronic acid.
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