Isopropylamine → 6-Chloro-1-(propylamino)anthracene-9,10-dione
Reaction equation
C(N)(C)C.[CH2:5]([NH2:8])[CH2:6][CH3:7].C(N[C:13]1[C:26]2[C:25](=[O:27])[C:24]3[C:19](=[CH:20][CH:21]=[C:22]([Cl:28])[CH:23]=3)[C:18](=[O:29])[C:17]=2[CH:16]=[CH:15][CH:14]=1)CC>>[CH2:5]([NH:8][C:16]1[C:17]2[C:18](=[O:29])[C:19]3[C:24](=[CH:23][C:22]([Cl:28])=[CH:21][CH:20]=3)[C:25](=[O:27])[C:26]=2[CH:13]=[CH:14][CH:15]=1)[CH2:6][CH3:7]Participants
4
Procedure
If the procedure indicated is followed but isopropylamine is replaced by propylamine, 22 g of 1-propylamino-7-chloroanthraquinone are obtained. The nitrobenzene/methanol mother liquor is concentrated and the residue is treated with methanol and with a little nitrobenzene. After working up, 8 g of 1-propylamino-6-chloroanthraquinone are obtained.
Workup
- customare obtained