Reaction equation
[F:1][C:2]([F:13])([F:12])[C:3]1[CH:8]=[CH:7][C:6]([C:9]([NH2:11])=[S:10])=[CH:5][CH:4]=1.Br[CH2:15][CH:16]=O.Cl>C(O)C>[F:13][C:2]([F:1])([F:12])[C:3]1[CH:8]=[CH:7][C:6]([C:9]2[S:10][CH:15]=[CH:16][N:11]=2)=[CH:5][CH:4]=1Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
In a manner similar to Step B of Example 1, the reaction of 10.0 grams (0.0487 mole) of (4-trifluoromethylphenyl)thiocarboxamide, 125 ml of ethanol, 8.35 grams (0.0490 mole) of bromoacetaldehyde, and 2 ml of concentrated hydrochloric acid produced 5.5 grams of 2-(4-trifluoromethylphenyl)thiazole as a solid.
Sources & evidence
- ORD record
- ord-b34f6ddb17ac42a98ce05c0042e80386
- Source dataset
- uspto-grants-1989_12
- Patent number
- US04889867
Linked notes
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