2-Bromobenzoic acid → Potassium o-bromobenzoate
Reaction equation
[Br:1][C:2]1[CH:10]=[CH:9][CH:8]=[CH:7][C:3]=1[C:4]([OH:6])=[O:5].C([O-])([O-])=O.[K+:15].[K+]>CO>[K+:15].[Br:1][C:2]1[CH:10]=[CH:9][CH:8]=[CH:7][C:3]=1[C:4]([O-:6])=[O:5]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
To a solution of o-bromobenzoic acid (201.03 g, 1.0 mol) in MeOH (500 mL), K2CO3 (69 g, 1.0 mol) was added. The mixture was concentrated to give the desired product (239.1 g, 1.0 mol, 100%).
Workup
- concentrationThe mixture was concentrated
Sources & evidence
- ORD record
- ord-b4a99f89d297472d85cdefa58996d216
- Source dataset
- uspto-grants-2005_12
- Patent number
- US06972287B1
Reaction notes
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