[CH:1]([C:4]1[C:13]([N+:14]([O-])=O)=[C:12]2[C:7]([CH:8]=[CH:9][CH:10]=[N:11]2)=[CH:6][CH:5]=1)([CH3:3])[CH3:2].[Sn](Cl)Cl>Cl>[CH:1]([C:4]1[C:13]([NH2:14])=[C:12]2[C:7]([CH:8]=[CH:9][CH:10]=[N:11]2)=[CH:6][CH:5]=1)([CH3:3])[CH3:2]In a similar fashion using route 1 general procedure 4, 7-isopropyl-8-nitroquinoline (Intermediate 59) (670 mg, 3.09 mmol), tin (II) chloride (1.8 g, 9.3 mmol) and 6 N HCl (6 drops) gave the title compound (420 mg, 73%) which was used in the next step without purification.
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