1-Bromo-4-fluorobenzene → (4-Chloro-2-fluorophenyl)(4-fluorophenyl)methanol

HRID 561423

Reaction equation

HRID 561423 reaction equation
Br[C:2]1[CH:7]=[CH:6][C:5]([F:8])=[CH:4][CH:3]=1.[Cl:9][C:10]1[CH:17]=[CH:16][C:13]([CH:14]=[O:15])=[C:12]([F:18])[CH:11]=1.FC1C=CC(C(C2C=CC(C(F)(F)F)=CC=2)O)=CC=1>>[Cl:9][C:10]1[CH:17]=[CH:16][C:13]([CH:14]([C:2]2[CH:7]=[CH:6][C:5]([F:8])=[CH:4][CH:3]=2)[OH:15])=[C:12]([F:18])[CH:11]=1

Participants

4

Reactant 3

HCID 99931-Bromo-4-fluorobenzeneHCID 579773alpha-(4-Fluorophenyl)-4-(trifluoromethyl)benzenemethanolHCID 27249084-Chloro-2-fluorobenzaldehyde

Product 1

HCID 58392437(4-Chloro-2-fluorophenyl)(4-fluorophenyl)methanol

Procedure

The title compound was prepared starting from 4.60 g (26.28 mmol) of 4-bromofluorobenzene and 5.00 g (31.53 mmol) of 4-chloro-2-fluorobenzaldehyde in analogy to the synthesis of the compound from Example 80A. 4.45 g (66% of theory) of the title compound were obtained.

Workup

  1. customThe title compound was prepared

Sources & evidence

ORD record
ord-4eb600ba820a4f04a7489fc54f54436b
Source dataset
uspto-grants-2011_11
Patent number
US08063234B2

Linked notes

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