Hydrochloric Acid → H-(L)-Pal-NH2
Reaction equation
[NH:1](C(OC(C)(C)C)=O)[C@H:2]([C:10]([NH2:12])=[O:11])[CH2:3][C:4]1[CH:9]=[N:8][CH:7]=[CH:6][CH:5]=1.Cl>C(Cl)Cl.O1CCOCC1>[NH2:1][C@H:2]([C:10]([NH2:12])=[O:11])[CH2:3][C:4]1[CH:9]=[N:8][CH:7]=[CH:6][CH:5]=1Participants
5
Reagents, catalysts & solvents 2
Procedure
Suspend Boc-(L)-Pal-NH2 (0.98 g) in methylene chloride (15 mL) with light heating and add a solution of hydrochloric acid (4M, 10 mL) in dioxane. After 30 minutes evaporate methylene chloride and dioxane. Dissolve the solid in methanol, precipitate by addition of ether and filtrate to give H-(L)-Pal-NH2. 2HCl (0.86 g, 98%).
Workup
- temperatureheating
- customAfter 30 minutes evaporate methylene chloride and dioxane
- dissolutionDissolve the solid in methanol
- additionprecipitate by addition of ether and filtrate
Sources & evidence
- ORD record
- ord-d6373623d39543ca934f731c9d5e46e1
- Source dataset
- uspto-grants-1998_06
- Patent number
- US05766932
Reaction notes
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