2-Ethylhexanoic Acid → Yttrium
Reaction equation
C([O-])(=O)C.[Y+3:5].C([O-])(=O)C.C([O-])(=O)C.[CH2:14]([CH:16]([CH2:20][CH2:21][CH2:22][CH3:23])[C:17]([OH:19])=[O:18])[CH3:15]>>[Y:5].[CH2:14]([CH:16]([CH2:20][CH2:21][CH2:22][CH3:23])[C:17]([O-:19])=[O:18])[CH3:15].[CH2:14]([CH:16]([CH2:20][CH2:21][CH2:22][CH3:23])[C:17]([O-:19])=[O:18])[CH3:15].[CH2:14]([CH:16]([CH2:20][CH2:21][CH2:22][CH3:23])[C:17]([O-:19])=[O:18])[CH3:15].[Y+3:5]Participants
4
Procedure
A yttrium containing solution was prepared by mixing and reacting yttrium acetate with a stoichiometric excess of 2-ethylhexanoic acid to produce yttrium tri(2-ethylhexanoate) in 2-ethylhexanoic acid. The resulting solution contained 7.01 percent by weight yttrium, based on total weight.
Workup
- additionby mixing