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Lithium Hydroxide → 3-iodo-1-(tetrahydro-2H-pyran-2-yl)-1H-indazole-5-carboxylic acid

HRID 1529442
ノート
印刷プレビュー

反応式

HRID 1529442 の反応式
[I:1][C:2]1[C:10]2[C:5](=[CH:6][CH:7]=[C:8]([C:11]([O:13]C)=[O:12])[CH:9]=2)[N:4]([CH:15]2[CH2:20][CH2:19][CH2:18][CH2:17][O:16]2)[N:3]=1.[Li+].[OH-]>C1COCC1.CO>[I:1][C:2]1[C:10]2[C:5](=[CH:6][CH:7]=[C:8]([C:11]([OH:13])=[O:12])[CH:9]=2)[N:4]([CH:15]2[CH2:20][CH2:19][CH2:18][CH2:17][O:16]2)[N:3]=1
参加物実験手順後処理出典と根拠反応ノート

参加物

4

反応物 2

HCID 3939Lithium HydroxideHCID 67959982methyl 3-iodo-1-(tetrahydro-2H-pyran-2-yl)-1H-indazole-5-carboxylate

生成物 1

HCID 679598343-iodo-1-(tetrahydro-2H-pyran-2-yl)-1H-indazole-5-carboxylic acid収率 87%

試薬・触媒・溶媒 1

HCID 21899815MeOH tetrahydrofuran溶媒

実験手順

To a solution of methyl 3-iodo-1-(tetrahydro-2H-pyran-2-yl)-1H-indazole-5-carboxylate ((5.0 g, 12.9 mmol) in THF: MeOH (70:30) (50 mL) was added LiOH (3.10 g, 129.0 mmol) in one lot and the reaction was stirred at RT for 12 h. The solvent were removed in vacuo and the residue was diluted with water and quenched with 1N HCl (50 mL) to obtain off white precipitate. The suspension was stirred for 10 min and filtered and dried to give 3-iodo-1-(tetrahydro-2H-pyran-2-yl)-1H-indazole-5-carboxylic acid (4.2 g, 87%) as an off white solid. 1H NMR (400 MHz, DMSO-d6) δ ppm 13.09 (s, 1H), 8.03-8.06 (m, 2H), 7.84-7.86 (m, 1H), 5.93 (dd, 1 H, J=9.7, 2.3 Hz), 3.90 (d, 1 H, J=11.9 Hz), 3.74-3.76 (m, 1H), 2.35-2.41 (m, 1H), 1.97-2.00 (m, 2H), 1.69-1.80 (m, 1H), 1.41-1.58 (m, 2H).

後処理

  1. customThe solvent were removed in vacuo
  2. additionthe residue was diluted with water
  3. customquenched with 1N HCl (50 mL)
  4. customto obtain off white precipitate
  5. stirringThe suspension was stirred for 10 min
  6. filtrationfiltered
  7. customdried

出典と根拠

ORDレコード
ord-b9684e8207124513840230ef6a787be4
出典データセット
uspto-grants-2015_07
DOI
10.6084/m9.figshare.5104873.v1
特許番号
US09090593B2

反応ノート

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