[Cl:1][C:2]1[CH:14]=[CH:13][C:5]([C:6]([CH2:8][CH2:9][C:10](O)=[O:11])=O)=[CH:4][C:3]=1[OH:15].O.[NH2:17][NH2:18]>>[Cl:1][C:2]1[CH:14]=[CH:13][C:5]([C:6]2[CH2:8][CH2:9][C:10](=[O:11])[NH:17][N:18]=2)=[CH:4][C:3]=1[OH:15]3-(4-chloro-3-hydroxybenzoyl)propionic acid was cyclised with hydrazine hydrate in a similar manner to that described in Example 3 (i) to give 6-(4-chloro-3-hydroxyphenyl)-4,5-dihydro-3(2H)-pyridazinone.
読み込み中…