[F:1][C:2]1[CH:3]=[C:4]([NH:19][C:20](=[O:22])[CH3:21])[CH:5]=[CH:6][C:7]=1[S:8][C:9]1[CH:14]=[CH:13][C:12]([CH3:15])=[CH:11][C:10]=1[N+:16]([O-])=O.[NH4+].[Cl-]>[Fe]>[NH2:16][C:10]1[CH:11]=[C:12]([CH3:15])[CH:13]=[CH:14][C:9]=1[S:8][C:7]1[CH:6]=[CH:5][C:4]([NH:19][C:20](=[O:22])[CH3:21])=[CH:3][C:2]=1[F:1]The product from Example 39d was reduced with Fe and NH4Cl following the procedure from Example 237E to give the title compound.
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