[Br:1][C:2]1[CH:19]=[CH:18][C:5]([CH2:6][O:7][C:8]2[CH:13]=[C:12]([N+:14]([O-])=O)[CH:11]=[C:10]([Cl:17])[CH:9]=2)=[CH:4][CH:3]=1.[NH4+].[Cl-]>[Fe]>[Br:1][C:2]1[CH:19]=[CH:18][C:5]([CH2:6][O:7][C:8]2[CH:13]=[C:12]([NH2:14])[CH:11]=[C:10]([Cl:17])[CH:9]=2)=[CH:4][CH:3]=1The product from Example 196a was reduced with Fe and NH4Cl following the procedure from Example 237E to give the title compound.
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